Why does $e^{i\\pi}=-1$? - Mathematics Stack Exchange
Euler's formula describes two equivalent ways to move in a circle. Starting at the number $1$, see multiplication as a transformation that changes the number $1 \cdot e^ {i\pi}$. Regular …
Absolute value of complex exponential - Mathematics Stack …
Feb 8, 2015 · Can somebody explain to me why the absolute value of a complex exponential is 1? (Or at least that's what my textbook says.) For example: $$|e^ {-2i}|=1, i=\sqrt {-1}$$
Prove that $e^ {i\pi} = -1$ - Mathematics Stack Exchange
Oct 13, 2021 · Prove Euler's identity $e^ {i\theta} = \cos \theta + i \sin \theta$ using Taylor series. Then plug in $\theta = \pi$.
How does $e^ {\pi i}$ equal $-1$ - Mathematics Stack Exchange
I love how the OP said, "I put it into the calculator and it works". Love this, my favorite example of how non-intuitive math can be.
Explain why $e^ {i\pi} = -1$ to an $8^ {th}$ grader?
Apr 20, 2015 · @Jamie: FWIW, I first saw this fact outside of class in about 7th grade, saw it "formally" for the first time in pre-calculus, got a first non-rigorous proof in Calculus II, and …
How to prove Euler's formula: $e^{it}=\\cos t +i\\sin t$?
Aug 28, 2010 · Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and …
Why $e^{i(π/3)} \\ne -1$? - Mathematics Stack Exchange
Mar 30, 2018 · The community reviewed whether to reopen this question 4 years ago and left it closed: Original close reason (s) were not resolved
How can $i^i = e^ {-\pi/2}$ - Mathematics Stack Exchange
Apr 19, 2017 · Then go build some other numbers which behave the way you want instead.
Problem using Casio fx-991CE X calculator to solve "e^(i*pi)"
Aug 18, 2021 · I'm trying to solve e^ (i*pi) on a Casio fx-991CE X calculator. The calculator is in Complex mode (MENU>2:Complex). I Input e^ (i*pi) and press "=" and get an error ...
logarithms - how do i solve this complex variables equation ...
Oct 25, 2021 · How can I find all roots of logz=ipi/2? I tried to use the formula Logz=lnr+itheta, but I cannot do the next step.